4.9t^2+330t-3069=0

Solution for 4.9t^2+330t-3069=0 equation:

4.9t^2+330t-3069=0

a = 4.9; b = 330; c = -3069;
Δ = b2-4ac
Δ = 3302-4·4.9·(-3069)
Δ = 169052.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(330)-\sqrt{169052.4}}{2*4.9}=\frac{-330-\sqrt{169052.4}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(330)+\sqrt{169052.4}}{2*4.9}=\frac{-330+\sqrt{169052.4}}{9.8}
$